The same properties already considered for the integral of step functions remain unchanged for the Riemann integral. Their proof is not difficult: in some cases it can be obtained by simple generalisation of the same property for the integral of step functions, in other cases it is a simple consequence of the Vitali-Lebesgue theorem.
The linearity property can obviously be generalized to any finite number of functions as follows: if f_{1}, ... , f_{n} are functions integrable on the same interval [a,b], then c_{1}f_{1} + ... + c_{n}f_{n} is also integrable and , for any choice of the constants c_{1}, ... , c_{n}.
Observe that if two functions are not integrable, their sum may be integrable: it's enough to take a non integrable function and the opposite one, so the sum is zero. The same holds for the product and the quotient of two non integrable functions.
The comparison property has an important consequence: setting f(x)=0 you obtain , if g(x)≥0: the Riemann integral of a positive function is positive. The converse is not true: if the integral of a function is positive, the function is not necessarily positive. A simple example can be given using the function signum (as this is a step function its integral is easy to calculate): we have , but the function is not positive in the interval [-1,2].
As far as the absolute value property is concerned observe that the converse of the property is not true: the absolute value of a function may be integrable, while the function is not. Consider for example , whose absolute value is a constant function.