In order to prove that the function
is not Riemann integrable, let us consider the two constant
functions g(x)=0 (this is a lower step
approximation of f) and h(x)=1 (this is an
upper step approximation of f). Every lower step
approximation, s, of f must satisfy the
condition s(x) ≤ g(x), while every upper
step approximation, t, must satisfy the condition
t(x) ≥ h(x). This allows us to conclude
that the lower Riemann integral of f is zero, while the
upper Riemann integral is b-a. So the function is not
integrable